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A ball is dropped from a height of 36 feet

A ball is dropped from a height of 36 feet.  The quadratic equation:

\[d = \frac {1}{2}gt^2 \]

is used to culate the distance $\mathbf{d}$ the ball has fallen after $\mathbf{t}$ seconds.  The constant $\mathbf{g}$ is the acceleration of gravity, 9.8 m/s2.  How long does it take the ball to hit the ground?  (in this problem, as in problem 3, we’re ignoring air resistance)

Number: 

Using the formula:

d=21gt2


With the given g = 9.8 m/s^2, we will convert it to ft/s^2.
9.8 m x 3.28084 ft / 1 m
9.8 m = 32.1522 ft

Therefore, g = 32.1522 ft/s^2

Using the formula:




Using the formula:d=21gt2With

Using the formula:

d=21gt2


With the given g = 9.8 m/s^2, we will convert it to ft/s^2.
9.8 m x 3.28084 ft / 1 m
9.8 m = 32.1522 ft

Therefore, g = 32.1522 ft/s^2

Using the formula: