# Uniform-Motion Problem

Submitted by JM on Sat, 07/11/2009 - 22:46When a certain object travels at a **uniform** **rate** of $\mathbf{r}$ miles per hour for a **time** of $\mathbf{t}$ hours, then if $\mathbf{d}$ miles is the **distance traveled**, the formula to derive $\mathbf{d}$ is:

**\[ d = r \cdot t \]**

An algebraic problem involving the use of this formula is called **uniform-motion problem**. This is because in Physics, the object is assumed to move with a constant rate in every second along the way.

In applying the formula, we should always remember that the units of measurement of the **rate** $\mathbf{r}$, **time** $\mathbf{t}$, and **distance** $\mathbf{d}$ MUST be consistent. It means that if the distance is measured in **mile** and time in **hour**, then the **rate **must be expressed in *miles per hour*.

**Problem:**

One runner took **3 min 45 sec** to complete a race and another runner required **4 min** to run the same race. The rate of the faster runner is **0.4 m/sec** more than the rate of the slower runner. Find their rates.

**Solution:**

Since the given data for time in the problem is seconds, we choose second as a measurement of time. Because we want to determine the rates of the runner, we have the following definition:

$\mathbf{r:}$ the number of the meter per second in the rate of the rate slower runner

$\mathbf{r + 0.4:}$ the number of the meters per second in the of the faster runner

**Since each runner is in the same race, they travel equal distances.** This fact will be used to obtain an equation needed to solve the problem. Using the rate formula, we can make a table of data below. **Read more »**

# Investment Problem

Submitted by JM on Thu, 07/09/2009 - 22:45The word problem that follows can be classified as an **investment problem** because it is one involving income from an investment. The income can be in the from of interest, and in that case we use the formula

\[ I = P \cdot R\]

where $\mathbf{I}$ dollars is the annual interest earned when $\mathbf{P}$ dollars is invested at a rate $\mathbf{R}$ per year. The rate is usually given a percent; thus if the rate is **8 percent**, then $\mathbf{R=0.08}$.

**Investment Problem**

A main invested part of USD 15,000 at 12 percent and the remainder at 8 percent. If his annual income from the two investments is USD 1,456, how much does he have invested at each rate?

**Solution** **Read more »**

# Mixture Problem: Chemical Solutions

Submitted by JM on Wed, 07/08/2009 - 22:55A mixture problem can involve mixing solutions containing different percents of a substance in order to obtain a solution containing a certain percent of the substance. This is usually present in real-world problems in chemistry and other related sciences.

Another kind of mixture problem for which the method of solving is similar involves mixing commodities of different values to obtain a combination worth a specific sum of money.

**Read more »**

- 6209 reads
- Comments

# Geometry Problem

Submitted by JM on Tue, 07/07/2009 - 23:48**Problem: Rectangular Dimensions
**

If a rectangle has a length that is 3 feet less than four times its width and its perimeter is 19 feet, what are the dimensions?

**Solution**

We wish to determine the number of feet in each dimension of the rectangle.

$\mathbf{w:}$ the number of centimeters in the width of the rectangle

$\mathbf{4w-3:}$ the number of centimeter in the length of the rectangle

**Draw a Diagram**

# Application of Linear Equations

Submitted by JM on Fri, 07/03/2009 - 21:34In many applications in algebra, the real-world problems are stated in words. They are called * word problems*, and they give relationships between known quantities and unknown quantities to be determined. In this tutorial, we will solve word problems by using linear equations. There is no specific method to use. However, here are some steps that give a possible procedure for you to follow.